4[m-(4-2m)]=5(2m+4)

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Solution for 4[m-(4-2m)]=5(2m+4) equation:


Simplifying
4[m + -1(4 + -2m)] = 5(2m + 4)
4[m + (4 * -1 + -2m * -1)] = 5(2m + 4)
4[m + (-4 + 2m)] = 5(2m + 4)

Reorder the terms:
4[-4 + m + 2m] = 5(2m + 4)

Combine like terms: m + 2m = 3m
4[-4 + 3m] = 5(2m + 4)
[-4 * 4 + 3m * 4] = 5(2m + 4)
[-16 + 12m] = 5(2m + 4)

Reorder the terms:
-16 + 12m = 5(4 + 2m)
-16 + 12m = (4 * 5 + 2m * 5)
-16 + 12m = (20 + 10m)

Solving
-16 + 12m = 20 + 10m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-10m' to each side of the equation.
-16 + 12m + -10m = 20 + 10m + -10m

Combine like terms: 12m + -10m = 2m
-16 + 2m = 20 + 10m + -10m

Combine like terms: 10m + -10m = 0
-16 + 2m = 20 + 0
-16 + 2m = 20

Add '16' to each side of the equation.
-16 + 16 + 2m = 20 + 16

Combine like terms: -16 + 16 = 0
0 + 2m = 20 + 16
2m = 20 + 16

Combine like terms: 20 + 16 = 36
2m = 36

Divide each side by '2'.
m = 18

Simplifying
m = 18

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